\triangle ABC, pripsane rovnostranne $\triangle CBN, \triangle ACM$ Dokazujeme: $\triangle MCB\cong\triangle ACN$ podle věty SUS a, 60\degree + \gamma, b
\triangle ABC
a
60\degree + \gamma
b
Dokazujeme: \triangle CBP\cong\triangle ABT
\triangle CBP\cong\triangle ABT