notes/notes/ech/Příklady.md
2021-11-22 13:38:55 +01:00

1.2 KiB

tags
ech

Příklady

Redoxní

Br_2 + KOH \rightarrow KBr + KBrO_3 + H_2O
3Br_2^0 + 6KOH \rightarrow \textcolor{yellow}{5}KBr^{-I} + \textcolor{yellow}{1}KBr^{+V}O_3 + 3H_2O

Redukce Br^0 + 1e^- \rightarrow Br^{-I} 1 ==5== Oxidace Br^0 - 5e^- \rightarrow Br^V 5 ==1==


FeSO_4 + K_2Cr_2O_7 + H_2SO_4 \rightarrow Fe_2(SO_4)_3 + Cr_2SO_4 + H_2O
6Fe^{II}SO_4 + 1K_2Cr_2^{II}O_7 + 7H_2SO_4 \rightarrow \textcolor{yellow}3Fe_2^{III}(SO_4)_3 + \textcolor{yellow}1Cr_2^{III}SO_4 + 7H_2O

Ox: 2Fe^{II} - 2e^- \rightarrow Fe_2^{III} 2 ==3== Red: Cr_2^{VI} + 6e^- \rightarrow Cr_2^{III} 6 ==1==


Cr_2O_r + KNO_3 + K_2CO_3 \rightarrow K_2CrO_4 + CO_2 + KNO_3
\textcolor{yellow}1Cr_2^{III}O_3 + \textcolor{yellow}3KN^{V}O_3 + 2K_2CO_3 \rightarrow 2K_2Cr^{VI}O_4 + 2CO_2 + 3KN^{III}O_3

Red: N^V + 2e^- \rightarrow N^{III} 2 ==3== Ox: Cr^{III} - 6e^- \rightarrow Cr^{VI} 6 ==1==


HI + H_2SO_4 \rightarrow I_2 + S + H_2O
\textcolor{yellow}6HI^{-I} + 1H_2^{I}S^{VI}O_4^{-II} \rightarrow 3I_2^{0} + \textcolor{yellow}1S^0 + 4H_2O

Ox: I^{-I} - 1e^- \rightarrow I^{0} 1 ==6== Red: S^{VI} + 6e^- \rightarrow S^0 6 ==1==