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https://github.com/danbulant/notes
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vault backup: 2023-01-03 15:31:02
This commit is contained in:
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10 changed files with 205 additions and 20 deletions
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@ -12,8 +12,8 @@
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@ -999,6 +999,10 @@
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@ -190,6 +190,14 @@
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@ -4,16 +4,28 @@
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@ -77,7 +89,7 @@
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@ -94,7 +106,7 @@
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@ -141,7 +153,7 @@
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@ -10,5 +10,6 @@ $T=273K$ … $t=0\degree C$
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- [[fyz/Mechanika tekutin/Termodynamika/Celsiova teplotní stupnice|Celsiova teplotní stupnice]]
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- [[fyz/Mechanika tekutin/Termodynamika/Pokus - Měření účinnosti varné konvice|Pokus - Měření účinnosti varné konvice]]
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- [[fyz/Mechanika tekutin/Termodynamika/Termodynamická teplota|Termodynamická teplota]]
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- [[fyz/Mechanika tekutin/Termodynamika/Vnitřní energie, teplo - řešení příkladů|Vnitřní energie, teplo - řešení příkladů]]
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- [[fyz/Mechanika tekutin/Termodynamika/Vnitřní energie|Vnitřní energie]]
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%% Zoottelkeeper: End of the autogenerated index file list %%
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@ -0,0 +1,65 @@
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# Vnitřní energie, teplo - řešení příkladů
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$c=450J*kg*K^{-1}$
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$20*0.7E_K=_\Delta U$
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$20*0.7\frac12 m_k v^2=m_D * c *_\Delta T$
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$7m_K v^2=m_D c \Delta T$
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$v^2=\frac{m_D c \Delta T}{7m_K}$
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$v=\sqrt{\frac{m_D c \Delta T}{7m_K}}$
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$\{v\}=\sqrt{\frac{150*450(411-383)}{7*6000}}$
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$v=6.7m*s^{-1}$
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---
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$m_o=250g$
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$t_o=100\degree C$
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$m_v=975g$
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$t_o=20\degree C$
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$\Delta t=2\degree C$
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$Q_1=Q_2$
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$Q_1$ odevzdane teplo valecku
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$Q_2$ teplo prijate vodou
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$Q=m c \Delta T$
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$Q_1=250*c_1*2$
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$Q_2=975*4180*2$
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$250*c_1*2=975*4180*2$
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$c_1=\frac{m_2c_2(t-t_2)}{m_1(t_1-t)}$
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$c_1=\frac{0.975*4180*(22-20)}{0.250(100-22)}$
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$c_1=418 J*kg^{-1}*K^{-1}$
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---
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$Q_1=Q_2$
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$c_1=c_2$ (stejna kapalina)
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$m_1\cancel{c_1}(t_1-t)=m_2\cancel{c_2}(t-t_2)$
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$m_1=\frac{m_2(t-t_2)}{t_1-t}$
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$\{m_1\}=\frac{40(20-5)}{80-20}$
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$m_1=10kg$
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---
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$P_0=?$
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$\tau=2h$
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$V=4000L$
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$t_1=55\degree C$
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$t_2=30\degree C$
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$\eta=60\%$
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$P_0=\frac{P}{?}=\frac{\frac{Q}\tau}{\frac{?}1}=\frac{Q}{\tau\eta}$
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$P_0=\frac{mc\Delta t}{\tau\eta}=\frac{\rho Vc\Delta}{\tau\eta}$
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$\{P_0\}=\frac{10^3*4*4180(55-30)}{7200*0.6}$
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$P_0=96760W$
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@ -311,3 +311,98 @@ $$17x-5=6(x+1)$$
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$$17x-5=6x+6 |+5$$
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$$11x=11$$
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$$x=1$$
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----
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A
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$1+\log_8x=\log_8(6-x)+2\log_8x$
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$log_8x$ => $[x>0]$
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$log_8(6-x)$ => $[x<6]$
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$x\in(0;6)$
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$1=-\log_8x+\log_8(6-x)+2\log_8x$
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$1=\log_8\frac{6-x}x$
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$\log_88=\log_8\frac{6-x}x$
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$1=\log_88$
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$\log_8(8*x)=\log_8((6-x)x^2)$
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$8x=(6-x)x^2$
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$x(x^2-6x+8)=0$
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$x_1=0$
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$x^2-6x+8=0$
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$x(x-2)(x-4)=0$
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$x_2=2$
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$x_3=4$
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$x_1=0$ => $[x>0]$ => $x_1\ne0$
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$x_2=2$
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$x_3=4$
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---
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B
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$\log z-2=6\log^{-1}z-1$
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$\log z-2=\frac6{\log z}-1$
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$\log z-1=\frac6{\log z}$
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$[z>0]$
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$P=\log z$
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$[P\ne0]$
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$P-1=\frac6P$
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$P^2-P=6$
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$P^2-P-6=0$
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$(P-3)(P+2)=0$
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$P=3$
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$P=-2$
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$\log z=3$
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$z=10^3=1000$
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$\log z=-2$
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$z=10^{-2}=0.01=1\%=1/100$
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$z\in\mathbb{R}-\{1\}$
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$z=\{10^3;10^{-2}\}$
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---
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C
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$\log_256=2\log_2(7-x)-\log_2(x+7)+3$
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$\log_256=\log_2((7+x)^2)-\log_2(x+7)+3$
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$3=\log_28$
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$\log_256=\log_2((7+x)^2)-\log_2(x+7)+\log_28$
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$\log_256=\log_2\frac{(7+x)^2*8}{x+7}$
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$56=\frac{(7+x)^2*8}{x+7}$
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$56=\frac{(7^2+14x+x^2)8}{x+7}$
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$56=\frac{(42+14x+x^2)8}{x+7}$
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$56=\frac{8*42+8*14*x+8x^2}{x+7}$
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$56=\frac{336+112x+8x^2}{x+7}$
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$56x+7*56=336+112x+8x^2$
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$56x+392=336+112x+8x^2$
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$56x+56=112x+8x^2$
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$56=56x+8x^2$
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$\frac25*2=\frac{2*2}5$
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