feat(linter): implement @typescript-eslint/no-empty-interface

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Boshen 2023-07-01 21:04:57 +08:00
parent 83f69b1c61
commit 2e6cb6d3d2
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3 changed files with 163 additions and 0 deletions

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@ -54,6 +54,7 @@ oxc_macros::declare_all_lint_rules! {
eslint::use_isnan,
eslint::valid_typeof,
typescript::isolated_declaration,
typescript::no_empty_interface,
typescript::no_extra_non_null_assertion,
typescript::no_non_null_asserted_optional_chain
}

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@ -0,0 +1,91 @@
use oxc_ast::AstKind;
use oxc_diagnostics::{
miette::{self, Diagnostic},
thiserror::Error,
};
use oxc_macros::declare_oxc_lint;
use oxc_span::Span;
use crate::{context::LintContext, rule::Rule, AstNode};
#[derive(Debug, Error, Diagnostic)]
#[error("typescript-eslint(no-empty-interface): an empty interface is equivalent to `{{}}`")]
#[diagnostic(severity(warning))]
struct NoEmptyInterfaceDiagnostic(#[label] pub Span);
#[derive(Debug, Error, Diagnostic)]
#[error(
"typescript-eslint(no-empty-interface): an interface declaring no members is equivalent to its supertype"
)]
#[diagnostic(severity(warning))]
struct NoEmptyInterfaceExtendDiagnostic(#[label] pub Span);
#[derive(Debug, Default, Clone)]
pub struct NoEmptyInterface;
declare_oxc_lint!(
/// ### What it does
///
/// Disallow the declaration of empty interfaces.
///
/// ### Why is this bad?
///
/// An empty interface in TypeScript does very little: any non-nullable value is assignable to {}.
/// Using an empty interface is often a sign of programmer error, such as misunderstanding the concept of {} or forgetting to fill in fields.
/// This rule aims to ensure that only meaningful interfaces are declared in the code.
///
/// ### Example
/// ```javascript
/// interface Foo {}
/// interface Bar extends Foo {}
/// ```
NoEmptyInterface,
correctness
);
impl Rule for NoEmptyInterface {
fn run<'a>(&self, node: &AstNode<'a>, ctx: &LintContext<'a>) {
if let AstKind::TSInterfaceDeclaration(interface) = node.kind() {
if interface.body.body.is_empty() {
match &interface.extends {
None => {
ctx.diagnostic(NoEmptyInterfaceDiagnostic(interface.span));
}
Some(extends) if extends.len() == 1 => {
ctx.diagnostic(NoEmptyInterfaceExtendDiagnostic(interface.span));
}
_ => {}
}
}
}
}
}
#[test]
fn test() {
use crate::tester::Tester;
let pass = vec![
"interface Foo { name: string; }",
"interface Foo { name: string; }
interface Bar { age: number; }
// valid because extending multiple interfaces can be used instead of a union type
interface Baz extends Foo, Bar {}",
];
let fail = vec![
"interface Foo {}",
"interface Foo { props: string; } interface Bar extends Foo {} class Baz {}",
"interface Foo { props: string; } interface Bar extends Foo {} class Bar {}",
"interface Foo { props: string; } interface Bar extends Foo {} const bar = class Bar {};",
"interface Foo { name: string; } interface Bar extends Foo {}",
"interface Foo extends Array<number> {}",
"interface Foo extends Array<number | {}> {}",
"interface Bar { bar: string; } interface Foo extends Array<Bar> {}",
"type R = Record<string, unknown>; interface Foo extends R {}",
"interface Foo<T> extends Bar<T> {}",
"declare module FooBar { type Baz = typeof baz; export interface Bar extends Baz {} }",
];
Tester::new_without_config(NoEmptyInterface::NAME, pass, fail).test_and_snapshot();
}

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@ -0,0 +1,71 @@
---
source: crates/oxc_linter/src/tester.rs
expression: no_empty_interface
---
⚠ typescript-eslint(no-empty-interface): an empty interface is equivalent to `{}`
╭─[no_empty_interface.tsx:1:1]
1 │ interface Foo {}
· ────────────────
╰────
⚠ typescript-eslint(no-empty-interface): an interface declaring no members is equivalent to its supertype
╭─[no_empty_interface.tsx:1:1]
1 │ interface Foo { props: string; } interface Bar extends Foo {} class Baz {}
· ────────────────────────────
╰────
⚠ typescript-eslint(no-empty-interface): an interface declaring no members is equivalent to its supertype
╭─[no_empty_interface.tsx:1:1]
1 │ interface Foo { props: string; } interface Bar extends Foo {} class Bar {}
· ────────────────────────────
╰────
⚠ typescript-eslint(no-empty-interface): an interface declaring no members is equivalent to its supertype
╭─[no_empty_interface.tsx:1:1]
1 │ interface Foo { props: string; } interface Bar extends Foo {} const bar = class Bar {};
· ────────────────────────────
╰────
⚠ typescript-eslint(no-empty-interface): an interface declaring no members is equivalent to its supertype
╭─[no_empty_interface.tsx:1:1]
1 │ interface Foo { name: string; } interface Bar extends Foo {}
· ────────────────────────────
╰────
⚠ typescript-eslint(no-empty-interface): an interface declaring no members is equivalent to its supertype
╭─[no_empty_interface.tsx:1:1]
1 │ interface Foo extends Array<number> {}
· ──────────────────────────────────────
╰────
⚠ typescript-eslint(no-empty-interface): an interface declaring no members is equivalent to its supertype
╭─[no_empty_interface.tsx:1:1]
1 │ interface Foo extends Array<number | {}> {}
· ───────────────────────────────────────────
╰────
⚠ typescript-eslint(no-empty-interface): an interface declaring no members is equivalent to its supertype
╭─[no_empty_interface.tsx:1:1]
1 │ interface Bar { bar: string; } interface Foo extends Array<Bar> {}
· ───────────────────────────────────
╰────
⚠ typescript-eslint(no-empty-interface): an interface declaring no members is equivalent to its supertype
╭─[no_empty_interface.tsx:1:1]
1 │ type R = Record<string, unknown>; interface Foo extends R {}
· ──────────────────────────
╰────
⚠ typescript-eslint(no-empty-interface): an interface declaring no members is equivalent to its supertype
╭─[no_empty_interface.tsx:1:1]
1 │ interface Foo<T> extends Bar<T> {}
· ──────────────────────────────────
╰────
⚠ typescript-eslint(no-empty-interface): an interface declaring no members is equivalent to its supertype
╭─[no_empty_interface.tsx:1:1]
1 │ declare module FooBar { type Baz = typeof baz; export interface Bar extends Baz {} }
· ────────────────────────────
╰────