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https://github.com/danbulant/notes
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vault backup: 2022-10-11 21:26:18
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2 changed files with 61 additions and 2 deletions
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@ -13,7 +13,7 @@
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{
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"path": "/",
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"date": "2022-10-11",
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"size": 916496
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"size": 917393
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}
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],
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"activityHistory": [
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@ -858,7 +858,7 @@
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},
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{
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"date": "2022-10-11",
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"value": 960
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"value": 1857
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}
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]
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}
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@ -160,3 +160,62 @@ $\frac{27^x3^2\sqrt3}{g^x}=1$
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---
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$\sqrt[5]{(\frac43)^{1-x}}=(\frac34)^{x+3}$
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$(\frac43)^{\frac{1-x}5}=(\frac43)^{-x+3}$
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$\frac{1-x}5=-x-3$
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$1-x=-5x-15$
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$1=-4x-15$
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$16=-4x$
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$x=-4$
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$K=\{-4\}$
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---
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$0.4^{2x}*2.5=(\frac25)^{x+4}$
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$(\frac25)^{2x}\frac52=(\frac25)^{x+4}$
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$(\frac25)^{2x}(\frac25)^{-1}=(\frac25)^{x+4}$
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$(\frac25)^{2x-1}=(\frac25)^{x+4}$
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$2x-1=x+4$
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$x=5$
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$K=\{5\}$
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---
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$36=\frac{6^{x-5}}{\sqrt6}$
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$6^2=\frac{6^{x-5}}{6^{\frac12}}$
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$6^2=6^{x-5-\frac12}$
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$2=x-5-\frac12$
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$x=\frac{15}2$
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$K=\{\frac{15}2\}$
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---
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$\frac{\sqrt[3]7}{49^{x-2}}=343^x*\frac17$
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$\frac{7^{\frac13}}{7^{2*(x-2)}}=7^{3x}*7^{-1}$
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$7^{\frac13-2x+4}=7^{3x-1}$
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$\frac13-2x+4=3x-1$
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$\frac13+5=5x$
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$1+15=15x$
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$16=15x$
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$x=\frac{16}{15}$
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---
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$2^x=32-2^x$
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$2^x=2^5-2^x$
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$2^x+2^x=2^5$
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$(2*2)^x=2^5$
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$2^x=2^4$
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$x=4$
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---
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$5^{x+2}2-5^{x+1}=45$
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$5^x5^22-5^{x+1}=9*5$ /$:5$
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$5^x5*2-5^x=9$
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$10*5^x-5^x=9$
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$9*5^x=9$
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$5^x=1$
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$x=0$
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