vault backup: 2023-03-09 11:40:25

This commit is contained in:
Daniel Bulant 2023-03-09 11:40:25 +01:00
parent d81947db04
commit 9dd50290e3
5 changed files with 114 additions and 31 deletions

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@ -12,8 +12,8 @@
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@ -150,6 +150,14 @@
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@ -8,24 +8,24 @@
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@ -66,21 +66,9 @@
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@ -138,7 +126,7 @@
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@ -155,7 +143,7 @@
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View file

@ -46,6 +46,7 @@ $\cos\beta=\frac{x_B}1=x_B$
| $\tg \alpha$ | 0 | $\frac{\sqrt3}3$ | $1$ | $\sqrt3$ | - |
| $\cotg \alpha$ | - | $\sqrt3$ | $1$ | $\frac{\sqrt3}3$ | 0 |
$\sin^2x+\cos^2x=1$
---

View file

@ -561,3 +561,86 @@ $x=\tg^{-1}(-3)$
$x=-71\degree33'$
---
52/6 i
$\sqrt2\cos(4\pi+2x)=-1$
$t=4\pi+2x$
$\cos(t)=-\frac1{\sqrt2}$
$\frac{\sqrt2}2=\frac{1}{\sqrt2}$ … rozšířit $*\frac{\sqrt2}{\sqrt2}=\frac{\sqrt2}2$
$\cos(t)=-\frac{\sqrt2}2$
$t_1=\frac34\pi+2k\pi$
$4\pi+2x=\frac34\pi+2k\pi$
$2x=\frac34\pi+2k\pi-4\pi$
$2x=-3\frac14\pi+2k\pi$
$\underline{x=\frac{13}8\pi+k\pi}$
$t_2=\frac54\pi+2k\pi$
$4\pi+2x=\frac54\pi+2k\pi$
$2x=-\frac{11}4\pi+2k\pi$
$\underline{x=-\frac{11}8\pi+k\pi}$
---
$2\tg(x)\sin(3x)=\sqrt3\tg x$
$2\tg(x)\sin(3x)-\sqrt3\tg x=0$
$\tg(x)(2\sin(3x)-\sqrt3)=0$
$\tg(x)=0$
$\underline{x=k\pi}$
$2\sin(3x)-\sqrt3=0$
$2\sin(3x)=\sqrt3$
$sin(3x)=\frac{\sqrt3}2$
$t=3x$
$t=\frac\pi3+2k\pi$
$3x=\frac\pi3+2k\pi$
$\underline{x=\frac\pi9+\frac23k\pi}$
$\underline{x=\frac{2\pi}9+\frac23k\pi}$
3 sady řešení
---
$2\sin x\cos5x=\sqrt2\sin x$
$2\sin x\cos5x-\sqrt2\sin x=0$
$\sin x(2\cos5x-\sqrt2)=0$
$\sin x=0$
$x=0\degree+k180\degree$
$2\cos5x-\sqrt2=0$
$2\cos 5x=\sqrt2$
$\cos5x=\frac{\sqrt2}2$
$\cos t=\frac{\sqrt2}2$
$t_1=45\degree+k360\degree=5x$
$x_1=9\degree+k72\degree$
$t_2=315\degree=5x$
$x_2=63\degree+k72\degree$
---
$1-4\cos^2x=4\sin x$
$1-4\cos x\cos x=4\sin x$
$1-4\cos x\cos x-4\sin x=0$
$4\cos^2 x-4\sin x-1=0$
$4\cos^2x-4\cos(x-\frac12\pi)-1=0$
$\sin^2x+\cos^2x=1^2$
$\cos^2x=1-\sin^x$
$1=4\sin x+4\cos^2x$
$1=4\sin x+4(1-\sin^2x)$
$1=4\sin x+4-4\sin^2x$
$k=\sin x$
$4k^2-4k-3=0$