vault backup: 2023-04-11 14:23:47

notes/.obsidian/plugins/obsidian-activity-history/data.json

@@ -13,7 +13,7 @@
     {
       "path": "/",
       "date": "2023-04-11",
-      "size": 1014211
+      "size": 1014853
     }
   ],
   "activityHistory": [
@@ -1170,7 +1170,7 @@
         },
         {
           "date": "2023-04-11",
-          "value": 21469
+          "value": 22111
         }
       ]
     }

notes/.obsidian/workspace.json

@@ -232,6 +232,8 @@
   },
   "active": "7da30d7b50ee03bc",
   "lastOpenFiles": [
+    "data/Pasted image 20230411141819.png",
+    "data/Pasted image 20230411141429.png",
     "mat/mat.md",
     "mat/Trigonometrie.md",
     "mat/Untitled",
@@ -258,7 +260,6 @@
     "cjl/literatura/slohy/Realismus/Realismus.md",
     "cjl/literatura/slohy/Romantismus/Karel Hynek Mácha.md",
     "cjl/literatura/slohy/Romantismus/Kytice.md",
-    "cjl/literatura/poznávání žánrů.md",
     "cjl/literatura/slohy/Realismus",
     "cjl/literatura/slohy/Poetismus",
     "data/Pasted image 20230402153918.png",
@@ -270,7 +271,6 @@
     "data/Screenshot_20230402_150005.png",
     "data/Pasted image 20230402145902.png",
     "data/Pasted image 20230402145720.png",
-    "data/Pasted image 20230402145615.png",
     "fyz/Pevne blbosti",
     "Untitled.canvas"
   ]

notes/mat/Trigonometrie.md

@@ -15,4 +15,35 @@ goniometrické, thaletova a pythagorova platí pouze pro pravoúhlý $\triangle$
 
 ## Euklidovy věty
 - pouze pro pravoúhlé $\triangle$
-- 
+
+![](Pasted%20image%2020230411141429.png)
+$P$ … pata výšky
+
+$c_b=|AP|$
+$c_a=|PB|$
+
+$c_b*c_a=v^2$
+$c_bc=b^2$
+$c_ac=a^2$
+
+---
+
+## Příklady
+
+P87/37, pravoúhlý $\triangle$
+$v=8cm$, $b=10cm$, $c=?$
+
+Pythagorova věta pro $\triangle ACP\rightarrow c_b$
+$c_b=\sqrt{b^2-v^2}=\sqrt{100-64}=\underline{6cm}$
+![](Pasted%20image%2020230411141819.png)
+
+$\triangle ABC\rightarrow c$
+$c_bc=b^2$
+$c=\frac{b^2}{c_b}=\frac{100}6=\underline{\frac{50}3cm}$
+
+$\triangle ABC\rightarrow a$
+$c_ac=a^2$
+$a=\sqrt{c_ac}$
+$c_a=c-c_b=\frac{32}3$
+$a=\sqrt{\frac{32}3\frac{50}3}$
+$a=\sqrt{\frac{1600}9}=\underline{\frac{40}3cm}$