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10
notes/.obsidian/workspace.json
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10
notes/.obsidian/workspace.json
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},
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"active": "2592a9fb4ab27d74",
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"fyz/Mechanika tekutin/Proudění/Proudnice.md",
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"fyz/Mechanika tekutin/Proudění/Rozdělení.md",
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"fyz/Mechanika tekutin/Příklady 14.11..md",
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"fyz/Mechanika tekutin/Proudění/Proudnice.md",
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"fyz/Mechanika tekutin/Proudění/Rozdělení.md",
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"fyz/Mechanika tekutin/Proudění/Hmotnostní tok.md",
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"fyz/fyz.md",
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"psi/vlan.md"
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@ -6,6 +6,10 @@ $$
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Součet kinetické a tlakové potenciální energie kapaliny o jednotkovém objemu je ve všech částech vodorovné trubice stejný.
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$$
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\frac12\rho v^2_1+p_1=\frac12\rho v^2_2+p_2
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$$
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## Rychlost výtékání kapaliny z nádoby
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@ -119,3 +119,27 @@ $v_2=\frac{60}{20}$
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$v_2=3ms^{-1}$
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Zúženou částí voda protéká rychlostí $3ms^{-1}$.
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---
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Potrubím s průřezem $50cm^2$ proudí voda rychlostí $4ms^{-1}$ při tlaku $200kPa$. Určete rychlost a tlak vody v zúženém průřezu $10cm^2$
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$S_1v_1=S_2v_2$
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$v_2=\frac{S_1v_2}{S_2}$
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$v_2=\frac{50*10*4}{10*10^{-4}}=20ms^{-1}$
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$p_2=\frac12\rho v_1^2+p_1-\frac12\rho v_2^2$
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$p_2=\frac12\rho(v_1^2-v_2^2)+p_1$
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$p_2=\frac12*1000(4^2-20^2)+2*10^{5}$
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$p_2=8kPa$
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---
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Ve vodorovné trubici proudí voda rychlostí $2.24ms^{-1}$ při tlaku $100kPa$. Jakou rychlostí proudí v zúženém místě, kde byl naměřen tlak $90kPa$?
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$v_1=2.24ms^{-1}$
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$p_1=100kPa$
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$p_2=90kPa$
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$\frac12\rho v_1^2+p_1=\frac12\rho v_2^2+p_2 \space|*2$
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$\rho v_1^2+2p_1-2p_2=\rho v_2^2$
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$v_2=\sqrt{v_1^2+\frac{2(p_1p_2)}{\rho}}$
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