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https://github.com/danbulant/notes
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vault backup: 2023-04-04 13:19:23
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3 changed files with 28 additions and 2 deletions
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@ -13,7 +13,7 @@
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{
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{
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"path": "/",
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"path": "/",
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"date": "2023-04-04",
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"date": "2023-04-04",
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"size": 991266
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"size": 991493
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}
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}
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],
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],
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"activityHistory": [
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"activityHistory": [
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@ -1158,7 +1158,7 @@
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},
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},
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{
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{
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"date": "2023-04-04",
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"date": "2023-04-04",
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"value": 1941
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"value": 2168
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}
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}
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]
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]
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}
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}
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@ -230,6 +230,14 @@
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"lastUpdated": 1680604049764
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"lastUpdated": 1680604049764
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}
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}
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}
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}
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},
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"2\\cos\\frac{\\alpha+\\beta}2\\sin\\frac{\\alpha-\\beta}2": {
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"2\\cos\\frac{\\alpha+\\beta}2\\sin\\frac{\\alpha-\\beta}2": {
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"currentFile": {
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"count": 1,
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"lastUpdated": 1680606991534
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}
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}
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}
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}
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}
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}
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}
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}
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@ -29,3 +29,21 @@ $x=k\frac{\pi}3+\frac\pi6$
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$\sin(-2x)=0$
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$\sin(-2x)=0$
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$-2x=k\pi$
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$-2x=k\pi$
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$x=-k\frac{\pi}2$
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$x=-k\frac{\pi}2$
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---
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$\cos x+\cos(3x)=0$
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$\cos\alpha+\cos\beta=2\cos\frac{\alpha+\beta}2\sin\frac{\alpha-\beta}2$
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$0=2\cos\frac{x+3x}2\sin\frac{x-3x}2$
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$0=2\cos\frac{4x}2\sin\frac{-2x}2$
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$0=2\cos(2x)\sin(-x)$
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$0=\cos(2x)\sin(-x)$
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$\sin(-x)=0$
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$-x=k\pi$
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$x=-k\pi$
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$\cos(2x)=0$
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$2x=k\pi+\frac\pi2$
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$x=k\frac\pi2+\frac\pi4$
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