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Daniel Bulant 2022-11-29 12:35:16 +01:00
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notes/fyz/Mechanika tekutin/Proudění/Odporová síla.md
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@ -50,3 +50,5 @@ $\{v_2\}=\frac{\cancel{\pi} r_1^2=v_1}{\cancel{\pi} r_2^2}$
$v_2=\frac{(2*10^{-2})^2*1.25*}{(0.5*10^{-2})^2}$
$v_2=\frac{4*1.25}{0.5^2}$
$v_2=20ms^{-1}$
$p_2=0Pa$